NOJ1009 2的N次方

循环的地方需要稍微注意下

#include <bits/stdc++.h>

int main() {
    int N;
    std::cin >> N;
    int result[400], length = 1;
    memset(result, 0, sizeof(result));
    result[0] = 1;

    for (int i = 1; i <= N; ++i) {
        // 进位不能放在循环中计算,小黄鸭一下就懂了.....我自己傻逼了半天
        int doPlusOne = 0;
        for (int j = 0; j < length; ++j) {
            result[j] = result[j] * 2 + doPlusOne;
            doPlusOne = result[j] / 10;
            result[j] = result[j] % 10;
            if (doPlusOne != 0 && j + 1 == length) {
                length++;
            }
        }

    }


    for (int i = 0; i < length; ++i) {
        std::cout << result[length - i - 1];
    }
    return 0;
}