NOJ1008 第几天

比较简单，主要是需要稍微算一下，原本想用时间戳偷懒的后来发现不如直接算….

#include <bits/stdc++.h>

const int dayPerMonth[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

int main() {
    while (true) {
        int year, month, day;
        std::cin >> year;
        if (year != -1) {
            std::cin >> month >> day;
            int leapYear = 0, sum = 0;
            // 闰年总数计算
            for (int i = 2000; i < year; ++i) {
                if ((i % 4 == 0 && i % 100 != 0) || i % 400 == 0) {
                    leapYear++;
                }
            }

            // 当年天数计算
            for (int i = 0; i < month; ++i) {
                sum += dayPerMonth[i];
            }
            if (((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) && month >= 2) {
                sum++;
            }
            sum += day;

            // 总天数计算
            int totalsum = sum;
            totalsum += (year - 2000 - leapYear) * 365 + 366 * leapYear - 1;
            std::cout << totalsum << std::endl << sum << std::endl;
        } else {
            break;
        }
    }
    return 0;
}